Create a Bootable USB By CMD

To Create a Bootable USB Drive, We need to use Command Prompt, To Create a Bootable USB Drive, we require minimum of 4GB USB to use it as a Windows installation media. You can also use minimum than 4GB but larger capacity is better. Here is the Step by Step Tutorial to Create a Bootable USB by CMD:

How to Create a Bootable USB By CMD?

• Insert USB Drive to your PC and run Command Prompt as an administrator.

Press Win+R to open RUN and than search for CMD.

•  Type "diskpart" on Command Prompt (without quotes) and hit Enter. wait for diskpart Program to run.
• Type "list disk" and Press Enter to view active disks on your PC.

• Than type "select disk 1" to select the disk 1.
• Now, Type "clean" to Format the drive.
• Type "create partition primary" and press Enter to create it a Primary Partition.
• Than type "select partition 1" and press Enter to select Partition 1 as active.
•  Type "active" to active Partition.
• Type "Format fs=ntfs quick" and Press Enter to Format the current Partition as NTFS File System.
• Type "exit" and press Enter to leave diskpart. but don't close the Command Prompt as it is required.

Assume that the USB Drive is the G: and the DVD Installer is located on f:

• In Command Prompt, Type "f:" and press Enter and the activate directory changed to f: 
• Type "cd boot" and press Enter to Active directory changed to F:\Boot>
• Type "bootsect/nt60 g:" and press Enter to create boot sector on G: Drive ( USB Drive)
• Type "exit" and Press Enter to close the Command Prompt.
• To install windows from a Bootable USB Drive, Just copy the Windows Setup in USB Drive.

After copying USB Drive is ready to be used for installing windows from USB Drive.